Structural

# Manual Beam Design

BEAM  DESIGN

1.DATA

L=3000mm

Wall Support=230Mm

2.EFFECTIVE SPAN OF BEAM:

Effective Span =c/c of support

= 3230 mm

3.SIZE OF BEAM:

Effective depth=Span/12

=269.16mm , Say 270mm

Clear cover=25mm,Use 16 mm ø

D=303 mm, Say 310 mm

D=310mm

d = 277mm, Say 280mm

d=280mm

Self Weight                           =1× 0.31× 0.135× 25=1.046KN/m

Factored Load     =23.694KN/m,  Factored BM=Wl2/8      = 30.89KN/m

1. TO GET AST:

Ast(Required)   = 388.33mm2

Numbers  of rods = 2nos

Provide 2nos of  16mmø rods

1. CHECK FOR MINIMUM & MAXIMUM AST:

ASTmin=(0.85/Fy) bd =77.421mm2

ASTmax=0.04 bd=1512mm2

7.CHECK FOR SHEAR:

Nominal shear stress < permissible shear  stress

ڂv =K ڂڂ    & v=Vu/bd

Vu=38.26KN ,      ڂv=1.012N/mm2

Permissible shear stress (K ڂc)

100Ast/bd=1.026N/mm2

Refer  From  Table 19 for I.S. 456

ڂc  = 0.625,  ڂcmax=2.8 N/mm2

See More  Doubly Reinforced Beam

ڂ v      > ڂc    >    ڂcmax

K ڂc=1×0.625=0.652N/mm2

8.SHEAR REINFORCEMENT:

Vus  =V–  ڂcbd

Vus  =14.625× 103 N

Provided 8mmø rods  @ 2 legged Stirrups

1) Sv= ( 0.87 Fy  Asv d/ Vus)

=694.41mm, Say 690 mm

2) Sv= ( 0.8 7 Fy Asv / bd)

=96.01mm < Say 100mm

3)  0.75 d= 210mm

4)  450mm

Provide 8mmø rods & 2 Legged  Stirrups  @ 100mm c/c

9.CHECK  FOR DEFLECTION:

FS=O.58 fy

Fs=240.7N/mm2                                                                   [M.F=2,  BV=20]

Effective  depth=Span/(BV×MF)

=80.75mm

80.75mm < 280mm

Hence it is safe

More Design Design of Stair Case

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### One Comment

1. Harmeet Singh says:

Sir please tell about design of beam by limit state method by giving a general example..

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