Structural

# RCC COLUMN WITH FOUNDATION

Design of RCC COLUMN WITH FOUNDATION

Reinforced Cement Concrete) column is a structural member of RCC frame structured building.

Earthwork in excavation in foundation:

1×2.00×2.00×0.83= 3.32CUM

(0.75M trapezoidal portion height+0.08M concrete)

Cement concrete 1:4:8 in base:

1×2.00×2.00×0.08= 0.32CUM

R.C.C work 1:2:4: in footing excluding steel and it’s bending.

Bottom square portion

1×2.00×2.00×0.25= 1.00CUM

Trapezoidal portion Vol

h/6(A1+A2+4Am)

0.5/6{(2×2+.35x.35+4[(2+.35)/2]x[(2+.35)/2]}=0.804CUM

Total : 1.00+0.804= 1.804CUM

R.C.C work 1:2:4: in column above Ground Level (G.L) excluding steel and it’s bending

Square portion below plinth level (P.L)

1x.35x.35×60 = 0.074 CUM

Circular portion above plinth level

1x(π/4×0.30×0.30)x3.30 = 0.233 CUM

Total:  0.074+0.233 = 0.307 CUM

Steel reinforcing bars including bending-

(i)                12 mm dia bars @0.89kg in base footing

No. of bars = (200cm-8cm)/15cm+1= 14Nos.

(Bars are spaced at 15cm  centre to centre and cover 8cm less, 4cm in one side + 1 bar is added)

L=200-2covers+2hooks = 200-2×4+2x9x1.2 = 213.6cm,  say 2.14m

(cover=4cm, hook = 9xd, d is diameter of bar 12mm = 1.2cm)

Bars are placed two way so

2x14Nos.x2.14m (Bar length) = 2x14x2.14 = 53.33 Kg.

(ii)              16mm diameter dowel bars@ 1.58 kg

L= 0.45+0.75-2xcover+bend on the concrete

= 0.45+0.75-2x.04+0.15 (overlap 41cm+4cmcover=45cm)

= 1.27m , take 6 Nos. dowel bars 60° apart.

=6Nosx1.27×1.58 = 12.40kg

(iii)            16mm dia vertical bars @ 1.58kg in column

L = 3.30+0.6+0.10+0.10 =4.10m, take 6 Nos bars at 60° apart.

6Nosx4.1×1.58 = 38.87Kg

(iV)      10mm Dia bars @ 0.62kg in lateral ties

No.= 3.90/.15+1 = 27Nos.

L = πx.22+18×1.0 (18xd) = .88m

27Nosx0.88×0.62 = 14.73kg.

Total weight:   53.33+12.04+38.87+14.73 = 118.97kg

ABSTRACT :

1. Earthwork in excavation in foundation: 3.32cum
2. Cement concrete 1:4:8 in base: 0.32cum
3. R.C.C work 1:2:4: in footing excluding 1.804cum

Steel and it’s bending.

1. R.C.C work 1:2:4: in column above Ground 0.307cum

Level (G.L) excluding steel and it’s bending

1. Steel reinforcing bars including bending- 118.97kg

Centering & shuttering required:

(a)  Footing trapezoidal portion- 4Nos.x(2.00+0.35)/2xsloping height

=4×1.175×0.964

4.531 sqm

(b) Square portion above G.L up to plinth- =4Nos.x0.35×0.6

= 0.840 sqm

(c.) Circular portion above plinth-

=πx0.3×3.3

=3.109sqm

Total= 4.531+0.84+3.109 = 8.48sqm

### Thomas Britto

I am Thomas Britto here to share my experiences in the civil engineering field to all my readers.Today many students are struggling to buy books at high prices. So I decided to start a blog and share my experience and knowledge with all my readers.